Question

For a polynomial P(x), the quotient P(x)/(x-2) has a remainder of 12. What is the value of P(2)? Please explain.

Answer 1

We have the following:

`(P\mleft(x\mright))/(x-2)=12`

Therefore:

`\begin{gathered} P(x)=12\cdot(x-2) \\ P(x)=12x-24 \end{gathered}`

now, x = 2

`\begin{gathered} P(2)=12\cdot2-24=24-24 \\ P(2)=0 \end{gathered}`