Question

An aqueous solution was prepared by dissolving 266.07 g of AgNO3 ( 169.88 g/mol) in enough water to make a total volume of 250.0 ml. What is the molarity of the solution

Answer 1

The correct answer is 6.265 M.

Step-by-step explanation:

To find the molarity of the solution, we first must recall that molarity represents the number of moles of solute divided by the number of liters of solution. Thus, our first step should be to convert the solute amount in grams to moles, using the given molar mass.

266.07 g * (1 mol/169.88 g) = 1.5662 mol

Now, we can find the molarity using the following formula:

Molarity = moles solute/liters solution

M = 1.5662 mol/0.25 L

M = 6.265 M

Therefore, the molarity of the solution is 6.265 M.

Hope this helps!