Question

Determine all Zeros(x-3)(x+4)(x+15)

Answer 1

(6x72) there you go

Answer 2

For this case we can do the following:

(x-3)(x+4)(x+15) =0

And we can find the zeros on this way:

x-3 =0

x=3

x+4 =0

x= -4

x+15=0

x=-15

then the zeros are:

x= -15, -4, 3