
1) Let's locate the endpoints of that line segment on the Plane.
2) Point A ( (1,4) and Point B (4,6) so let's find the length of that segment using the distance formula, derived from the Pythagorean Theorem
![\begin{gathered} d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/whl55ykd5e8cqln85kpwi6zfxcihkym9om.png)
So now, let's plug those coordinates into that.
2.2)
![\begin{gathered} d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ d=\sqrt[]{(4_{}-1_{})^2+(6-4_{})^2} \\ d=\sqrt[]{13}\approx3.6 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/k0rx37zq9ogr4p561vxdfi9w0135esie9o.png)
Notice that we could have found this length had we used the Pythagorean Theorem since this is a small triangle.
3) Thus, the answer is 3.6