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Solve for ,"a" in 3(a+2)/4 +3/2=0

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Answer:


a=6

Explanation:

To solve the following equation:


(3)/(a)-(4)/(a+2)=0_{}

Multiply all terms by a(a+2) and cancel:


\begin{gathered} (3(a(a+2)))/(a)-(4(a(a+2)))/(a+2)_{}=0(a(a+2)) \\ 3(a+2)-4a=0 \end{gathered}

Apply distributive property of multiplication to expand:


3a+6-4a=0

Now, use inverse operations to solve equations and isolate a:


\begin{gathered} -a+6=0 \\ a=6 \end{gathered}

User DrBug
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