ANSWER
Perimeter = 70
Sketch:
Step-by-step explanation
Step 1: Given
A (4,0),B(24,0) and C (24,21)
Step 2: find the length of AB
![\begin{gathered} AB\text{ = }\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ AB\text{ = }\sqrt[]{(24-4)^2+(0-0)^2} \\ AB\text{ = }\sqrt[]{20^2} \\ AB\text{ = }\sqrt[]{400}\text{ = 20} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/fxfpffi6x199fyue49pzoggo9ndqcqumzs.png)
Step 3: find the length of AC
![\begin{gathered} AC\text{ = }\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ AC\text{ = }\sqrt[]{(24-4)^2+(21-0)^2} \\ AC\text{ = }\sqrt[]{20^2+21^2} \\ AC\text{ = }\sqrt[]{400+441} \\ AC\text{ = }\sqrt[]{841}\text{ = 29} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/6tnh09wvt1oz6u5eq7f31za1ghvg3t9ssv.png)
Step 4: find the length of BC
![\begin{gathered} BC\text{ = }\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ BC\text{ = }\sqrt[]{(24-24)^2+(21-0)^2} \\ BC\text{ = }\sqrt[]{21^2} \\ BC\text{ = }\sqrt[]{441}\text{ = 2}1 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ya4m2mcv57cws9sn4bkgw6ehj6s6wbkeb6.png)
Step 5: find the perimeter of triangle ABC

Hence, the perimeter of triangle ABC is 70.