Question

What is the equation of a line with a slope of 6 and a y-intercept of -2? A. y= -2x+ 6B. y= 6x +2C. y= 2x+6D. y= 6x-2

Answer 1

Given slope of a equation is 6 and y-intercept 2.

Now, from option D, y = 6x-2

We can write it as:

`\begin{gathered} 6x-y=2 \\ (x)/((1)/(3))+(y)/(-2)=1 \end{gathered}`

So, we know intercept form

`(x)/(a)+(y)/(b)=1`

comparing with general equation, intercept of a equation is

`((1)/(3),-2)`

Now slope of y = 6x-2,

`(dy)/(dx)=6`

Hence, slope of y=6x-2 is 6 and y-intercept is -2.