1 Answer

Rick Wolff · Answer 1 · 2023-06-28T14:52:42+0000

Answer: 0.7995 or 79.95%

Given:

X~N(23.4, 6.64)

Where:

mean = 23.4

standard deviation = 6.64

First, let us find the z-score using the formula:

$z=(x-\mu)/(\sigma)$
z=(29-23.4)/(6.64)=0.84

Now, we need to look at the table and find the value of 0.8 under 0.04.

And here, we get .7995.

Therefore, the probability that the speed of a car is at most 29 is 0.7995 or 79.95%

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