77.4k views
3 votes
Find the partial sum.14.(-1)" (2n-1)n=5

1 Answer

3 votes

This requires us to add up the expression as the variable goes from n = 5 to n = 10.


(-1)^{n\text{ }}\text{ becomes 1 or -1 if n is even and odd respectively.}

And we know that when we substitute n between 5 to 10, we get

For n = 5, we have:

-1 x (2(5) -1) = -1 x 9 = -9

For n = 6, we have:

1 x (2(6) -1) = 1 x 11 = 11

For n = 7, we have:

-1 x (2(7) -1) = -1 x 13 = -13

For n = 8, we have:

1 x (2(8) -1) = 1 x 15 = 15

For n = 9, we have:

-1 x (2(9) -1) = -1 x 17 = -17

For n = 10, we have:

1 x (2(10) -1) = 1 x 19 = 19

Next, we add up all.

-9 + 11 + (-13) + 15 + (-17) + (19)= 6

Hence, answer is 6

User Antoniom
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories