Question

A 6-sided die is loaded in such a way where odd outcomes occur 2/9 of the time, and even outcomes happen the other 1/9 of the time. What is this die's expected value? 04.333 OB.4 OC. 35 OD. 3.25 Reset Selection

Answer 1

The odd outcome (1, 3 and 5) probability is 2/9, and the even outcome (2, 4 and 6) probability is 1/9. The expected value is given by:

`\begin{gathered} \sum_i^6i\cdot P(i)=(1+3+5)\cdot(2)/(9)+(2+4+6)(1)/(9)=2+(12)/(9)=3.33... \\ \end{gathered}`

Answer: Option A