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Factor completely: 2x2 – 8x – 10A) (2x+2)(x-5)B) 2(x+5)(x+1)C). (2x-10)(x+1)D) 2(x+5)(x-1)

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We are to factor the expression;


2x^2-8x-10

We go about it this way;

1. Multiply the constant with the second power term to obtain;


-20x^2

Lets obtain factors of this that adds up to give -8x, we have

-10x and 2x


\begin{gathered} 2x^2-10x+2x-10 \\ 2x(x-5)+2(x-5) \\ (2x+2)(x-5) \end{gathered}

Going through the options, we see that the correct solution is Option A

User Niranjan Sarvi
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