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A chemist working as a safety inspector finds an unmarked bottle in a lab cabinet. A note on the door of thebottles of chloroform, glycerol, dimethyl sulfoxide, diethylamine, and methyl acetate.The chemist plans to try to identify the unknown liquid by measuring the density and comparing to known derSafety Data Sheets (MSDS), the chemist finds the following information:liquid/densitychloroform1.5 g• mL-1glycerol-11.3 g. mLdimethyl sulfoxide1.1 g. m-1Dimethylamine0.71 g• mL-1methyl acetate0.93 g• mI-1Next, the chemist measures the volume of the unknown liquid as 1435. Cm^3 And the mass of the unknown liquid is 1.81 kg.Calculate the density of a liquid be sure your answer has the correct number of significant digits. ?g.mL-1Given the data above is it possible to identify the liquid? yes or noIf it’s possible to identify the liquid, do so.

A chemist working as a safety inspector finds an unmarked bottle in a lab cabinet-example-1
User Phoera
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The density of any substance corresponds to the volume occupied by a given mass. Density varies with temperature and pressure. In this case, we will assume that the temperature and pressure remain constant, therefore the density will also remain constant. To calculate the density we can apply the following equation


\text{Density = }\frac{\text{Mass}}{Volumen}

We have the following data:

Mass = 1.81 kg = 1810 g

Volume = 1435 cm^3 = 1435 mL

We replace the data into the equation,


\text{Density = }\frac{\text{1810 g}}{1435\text{ mL}}=\text{ 1.26 g/mL}

The density of the liquid is 1.26 g/mL

If we compare the density obtained with the measured compounds, we can verify that the glycerol has the same density.

Despite this, we cannot be sure that it corresponds to this substance, since as the container is not marked, the substance may contain a mixture of the substances contained in the rest of the bottles.

When mixing different substances with different densities, the final density will be an average, so it could also happen that by chance the density is equal to that of glycerol. Further laboratory analysis should be done to identify the unknown substance

User Abdennour TOUMI
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