Question

A right square pyramid has an altitude of 10 and each side of the base is six. To the nearest 10th of a centimeter what is the distance from the Apex or top of the pyramid to each vertex of the base?

Answer 1

Given the question on the question tab;

`\begin{gathered} Applying\text{ Pythagoras' Theorem: } \\ y^2=6^2+6^2 \\ y^2=36+36 \\ y^2=72 \\ y=√(72) \end{gathered}`
`\begin{gathered} Applying\text{ Pythagoras' theorem again;} \\ x^2=10^2+((√(72))/(2))^2 \end{gathered}`
`\begin{gathered} x^2=100+(72)/(4) \\ x^2=100+18 \\ x^2=118 \\ \end{gathered}`
`\begin{gathered} x=√(118) \\ x=10.9cm \end{gathered}`

Final answer:

10.9cm