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A company has a manufacturing plant that is producing quality clocks. They find that in order to produce 240 clocks in a month, it will cost $7760. Also, to produce 450 clocks in a month, it will cost $11750. Find an equation in the form y=mx+b, where x is the number of clocks produced in a month and y is the monthly cost to do so.Answer: y=

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Given the equation:


y=mx+b,

if you substitute the given data, you get the following system of equations:


\begin{gathered} 7760=240m+b, \\ 11750=450m+b. \end{gathered}

Subtracting the first equation from the second one, you get:


11750-7760=450m-240m+b-b.

Simplifying you get:


3990=210m.

Solving for m, you get:


m=(3990)/(210)=19.

Substituting m=3990 in the first equation, and solving for b you get:


\begin{gathered} 7760=19(240)+b, \\ b=7760-19(240), \\ b=3200. \end{gathered}

Answer:


y=19x+3200.

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