![48cm^2](https://img.qammunity.org/2023/formulas/mathematics/college/uq8c9yxc4hw2kdcmuf8dmc5o4sk545w4po.png)
Step-by-step explanation
Step 1
to find the total surface area we need to add the area of the six rectangles
Step 1
for rectangle 1 and rectangle 2
![\begin{gathered} \text{rectangle}1=\text{rectangle}2 \\ \text{area}=2\text{ cm }\cdot2cm=4cm^2 \\ \\ \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/1swvziyyqsijnmnlrv0qnis9opxzp9u5j6.png)
now, for rectangles 3 and 4
![\begin{gathered} \text{rectangle}3=\text{ rectangle4} \\ \text{Area}=2\text{ cm}\cdot\text{ 5 cm} \\ \text{Area}=10cm^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/386uf0ohvuipt6k4epcxsazkpuvf2swt01.png)
finally, for rectangle 5 and rectangle 6
![\begin{gathered} \text{rectangle}5=\text{rectangle}6 \\ \text{Area}=2\text{ cm}\cdot5\text{ cm} \\ \text{Area}=10cm^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/x2ccpv35u34ifp0fa5keugchl9gdx3y2hd.png)
Step 2
find the total surface area
![\begin{gathered} \text{total}=\text{Arec}1+\text{Arec2}+\text{Arec3}+\text{Arec4}+\text{Arec5}+\text{Arec}6 \\ \text{replacing} \\ \text{total}=4+4+10+10+10+10 \\ \text{total}=48cm^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ck465jh5l6t29r4xidxdivyanj0yvobn4r.png)
I hope this helps you