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F(x) = 10x^2+19x-10 solve by factoring

User John Breen
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\begin{gathered} \text{the discriminant b}^2-4ac\text{ will not give a p}\operatorname{erf}ectsquare. \\ a=10,\text{ b=19, c=-10} \\ \text{The general expression of a quadratic expression is} \\ ax^2+bx+c \\ so \\ b^2-4ac=19^2-(4\text{ }*10*-10)=361\text{ +}400=761 \\ \text{the square root of 761 is 27.586}\ldots.. \\ \text{the fractions shows the discriminant is not a p}\operatorname{erf}ect\text{ square} \end{gathered}

so this can only be solved using other methods of solving quadratic equation

such as using

quadratic formular

graphical method

completing the square

so there is no factor for this equation

User Bones
by
7.3k points

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