Question

Number 2 I need help on how to solve it

Answer 1

Let's simplify the following expression:

`\text{ }\frac{\text{ \lparen2x}^4\text{ - y}^6\text{z}^(-4))^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{\text{ 6x}^5\text{y}^(-4)\text{z}^(-5)}{\text{ \lparen2x}^6\text{y}^3\text{z}^(-3))^2}`

We get,

`\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^(-4))^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }(6x^5y^(-4)z^(-5))/((2x^6y^3z^(-3))^2)`
`\text{ }((2x^4-y^6z^(-4))^2(6x^5y^(-4)z^(-5)))/((2x^2z^3)(2x^6y^3z^(-3))^2)`
`\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^(-4)\text{ + y}^(12)z^(-8))(6x^5y^(-4)z^(-5))}{(2x^2z^3)(4x^(12)y^6z^(-6))}`
`\text{ }\frac{24x^(13)y^(-4)z^(-5)\text{ - 24x}^9y^2z^(-9)\text{ + 6x}^5y^8z^(-13)}{8x^(14)y^6z^(-3)}`