Given
centered at (3 , 5) and passes through (-2 , 9)
Find
Equation of the circle
Step-by-step explanation
an equation of the circle is given by
![(x-h)^2+(y-k)^2=r^2](https://img.qammunity.org/2023/formulas/mathematics/college/5s77z5lwu6jnvb5vkwanu2jvhq5sh1qkc3.png)
where (h ,k) be the center and r be the radius
we need to find the radius of circle.
here , we use distance formula to find radius.
points (3 ,5) and (-2 , 9)
![\begin{gathered} d=√((-2-3)^2+(9-5)^2) \\ d=√(25+16) \\ d=√(41) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ixy0e8ub4c76arxzyhm7qhi2d73hceeaas.png)
so , equation of circle is
![\begin{gathered} (x-3)^2+(y-5)^2=(√(41))^2 \\ (x-3)^2+(y-5)^2=41 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/uoi5axn415qvnj4xoh6c3p9lbl597pl9bj.png)
Final Answer
Hence , the correct option is D