Question

What is the equation of the line that passes through the point (4, -2) and has aslope of -2?

Answer 1

We can use the point-slope formula o find the equation of the line. The formula is the following:

`y-y_0=m(x-x_0)`

then, in this case we have the following:

`\begin{gathered} (x_0,y_0)=(4,-2) \\ m=-2 \\ \Rightarrow y-(-2)=-2(x-4) \\ \Rightarrow y+2=-2x+8 \\ \Rightarrow y=-2x+8-2=-2x+6 \\ y=-2x+6 \end{gathered}`

therefore, the equation of the line is y = -2x + 6