Question

Find the measure of

Answer 1

we have the following:

`<\text{JKM}=<\text{MKL}`

Therefore:

`(\sin (2x-3))/(4x-1)=(\sin (2x-3))/(35)`

solving for x:

`\begin{gathered} (2x-3)/(4x-1)=(2x-3)/(35) \\ 35\cdot(2x-3)=(4x-1)\cdot(2x-3)_{} \\ 70x-105=8x^2-14x+3 \\ 8x^2-84x+108=0 \\ 4\mleft(2x-3\mright)\mleft(x-9\mright)=0 \\ x=9 \end{gathered}`

therefore,

`<\text{JKM=2}\cdot9-3=18-3=15`