Question

A sample of N2 occupies a volume of 61 mL at 29 °C.What volume in mL will it occupy at 43 °C?

Answer 1

The final volume is 90.45mL

Explanation

Given information

The initial volume of the gas = 61mL

The initial temperature of the gas = 29 degrees Celcius

The final temperature of the gas = 43 degrees Celcius

From the given data, you will see that the pressure of the gas is constant.

To find the final volume of the gas, we will need to apply Charle's law

Charle's law state that "the volume of a given mass of a gas is directly proportional to its temperature, provided that the temperature of the gas remains constant"

This law can be translated mathematically below

`\begin{gathered} V\text{ }\propto\text{ T} \\ \text{ introduce the constant k} \\ V\text{ = KT} \\ \text{Divide both sides by T} \\ (V)/(T)\text{ = K} \end{gathered}`

where

V = volume

T = temperature

From the above mathematical expression, we can now find our final volume

Let the final volume be V2

`\begin{gathered} (V1)/(T1)\text{ =}(V2)/(T2) \\ (61)/(29)\text{ = }(V2)/(43) \\ \text{cross multiply} \\ 61\text{ }*\text{ 43 = V2 }*\text{ 29} \\ 2623\text{ = 29V2} \\ \text{Divide both sides by 29} \\ (2623)/(29)\text{ = }(29V2)/(29) \\ V2=\text{ 90.45mL} \end{gathered}`

Therefore, the final volume is 90.45mL