Question

What is an equation of the line that passes through the points (8,-4) and (6,-5)?

Answer 1

y=1/2x-8

Explanation:

m=(y2-y1)/(x2-x1)

m=(-5-(-4))/(6-8)

m=(-5+4)/-2

m=-1/-2

m=1/2

y-y1=m(x-x1)

y-(-4)=1/2(x-8)

y+4=1/2(x-8)

y=1/2x-8/2-4

y=1/2x-4-4

y=1/2x-8