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part 2...expression using numbers and variables....need help with number 3 ..hello please help me with my math summer package and explain it in a way that a 7th grader can understand it

part 2...expression using numbers and variables....need help with number 3 ..hello-example-1

1 Answer

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Step-by-step explanation:

Given:

The number of figurine dolls in one case is


55dolls\text{ }in\text{ }1case

Part A:

To figure out the number of figurine dolls in


750cases,

We will use the formula


number(dolls)=number(dolls\text{ per case\rparen}* number(cases)

By substituting the values, we will have


\begin{gathered} number(dolls)=number(dolls\text{percase}\operatorname{\rparen}*(number(cases) \\ number(dolls)=55*750 \\ number(dolls)=41250dolls \end{gathered}

Hence,

The final answer is


\begin{equation*} 41250dolls \end{equation*}

Part B:

To figure out the number of figurine dolls in


1000cases

By substituting the values, we will have


\begin{gathered} number(dolls)=number(dolls\text{percase}\operatorname{\rparen}* number(cases) \\ number(dolls)=55*1000 \\ number(dolls)=55000dolls \end{gathered}

Hence,

The final answer is


55000dolls

Part C:

To figure out the number of figurine dolls in


1250cases

By substituting the values, we will have


\begin{gathered} number(dolls)=number(dolls\text{percase}\operatorname{\rparen}* number(cases) \\ number(dolls)=55*1250 \\ number(dolls)=68750dolls \end{gathered}

Hence,

The final answer is


\begin{equation*} 68750dolls \end{equation*}

Part D:

Let the number of dolls be repressented by


d

To figure out the number of figurine dolls in


c\text{ }cases

By substituing the values, we will have


\begin{gathered} number(dolls)=number(dolls\text{percase}\operatorname{\rparen}* number(cases) \\ d=55* c \\ d=55c \end{gathered}

Hence,

The expression is given below as


d=55c

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