Question

What is the perimeter of a rectangular picture frame that is 14 1/2 inches tall and 11 1/2 inches wide?

Answer 1

You have a rectangular picture with the following sides:

-t: tall = 14 1/2

-w: wide = 11 1/2

You first exprese the previous numbers as normal fractions:

`\begin{gathered} 14\text{ }(1)/(2)=(14)/(1)+(1)/(2)=(28+1)/(2)=(29)/(2) \\ 11(1)/(2)=(11)/(1)+(1)/(2)=(22+1)/(2)=(23)/(2) \end{gathered}`

Next, you use the following formula for the perimeters of a rectangle

`P=2t+2w`

By replacing the values of t and w you obtain:

`P=2((29)/(2))+2((23)/(2))=29+23=52`

Hence, the perimeter of the given rectangle is 52 inches