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Solve the system by substitution. 3х – 8y = -506у = x

User Ram Patra
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1 Answer

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We have the linear system of equations:


\begin{gathered} 3x-8y=-50 \\ 6y=x \end{gathered}

and we have to solve it by substitution.

We can replace the value of x, that is 6y, in the first equation and solve for y:


\begin{gathered} 3x-8y=-50 \\ 3(6y)-8y=-50 \\ 18y-8y=-50 \\ 10y=-50 \\ y=(-50)/(10) \\ y=-5 \end{gathered}

Now we can calculate x as:


x=6y=6(-5)=-30

Answer: x=-30 and y=-5

User BadAdviceGuy
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