Question

5) When the equation, Zn(s) + NO3-(aq) NH4+(aq) + Zn2+(aq) is balanced for an acidic solution, the Zn/NO3- ratio is

Answer 1

Step-by-step explanation:

Here, we want to write an acidic ratio

We start by balancing the ionic equation as follows:

`4Zn_((s))+NO^-_(3(aq))+10H^+_{}\text{ }\rightarrow NH^+_(4(aq))+4Zn^(2+)_((aq))+3H_2O^{}_{}`

From what we have here, we have to check for the balance in terms of the number of atoms and the ions

From the balanced equation, we can see that 4 atoms of zinc reacts with a single ionic entity of the nitrate V

We have the ratio as:

`(4)/(1)\text{ = 4}`