To determine the area of the remaining paper, you have to subtract the area of the semicircle ( i.e. the area of a full circle) from the area of the rectangle.
Recall that the area of a circle is given by the following formula:
![A_c=\pi r^2,](https://img.qammunity.org/2023/formulas/mathematics/college/1hiz11tu1haoko53gs3xryzsmcpzoe9gzz.png)
where r is the radius. Now, the semicircles have a radius of 12cm/2=6cm, therefore, the area of the circle formed by the semicircles is:
![Ac=\pi(6cm)^2=3.14(36cm^2)=113.04cm^2.](https://img.qammunity.org/2023/formulas/mathematics/college/s3el6rwsotghax9w5zc3nxajro6cedogre.png)
The area of a rectangle is given by the following formula:
![A_r=wl,](https://img.qammunity.org/2023/formulas/mathematics/college/8ibg7e08wnpbtbc06kupvmhhlyz12oryc3.png)
where w=width, and l=lenght. Therefore, the area of the rectangle is:
![A_r=(24cm)(12cm)=288cm^2.](https://img.qammunity.org/2023/formulas/mathematics/college/3elwb2xfxoltohbxqu0th76hopeuvrolk2.png)
Finally, the area of the remaining paper is:
![288cm^2-113.04cm^2=174.96cm^2.](https://img.qammunity.org/2023/formulas/mathematics/college/mo956kat6erm2vwz47h7ds3a8dr64i8rm1.png)
Answer:
![174.96cm^2.](https://img.qammunity.org/2023/formulas/mathematics/college/i1oi53ghutg3aqrmaod0n2a3snkcxujwwy.png)