Draw a diagram to visualize the situation:
Notice that the vertical component of the velocity can be found using the sine trigonometric function:
![v_y=v\cdot\sin (2º)](https://img.qammunity.org/2023/formulas/physics/college/yhmwcj4kmlqpx4dxvxfqp5hpu9hqbqw9eq.png)
Substitute v=133.3m/s to find the vertical component of the velocity:
![v_y=133.3(m)/(s)*\sin (2º)=4.65(m)/(s)](https://img.qammunity.org/2023/formulas/physics/college/ejav9kqu1c2lg0hgm5i5u687rkdliosbd8.png)
Use the formula v=d/t to find the time that it takes for the plane to descend 500m. Isolate t:
![\begin{gathered} t=(d)/(v) \\ \Rightarrow t=(500m)/(4.65(m)/(s))=107.5s \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/ltjh3ostzqe470z8toc0ipqdfg1h3ext3b.png)
Then, the vertical component of the velocity is 4.65m/s (downwards) and it takes 107.5s to descend 500m.