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Find the density of a plastic triangular pyramid with a height of 5 feet. The base of the pyramid has a height of 4 feet and a base length of 3 feet. The mass is 56 kilograms.

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The base length of triangular pyramid is b = 3 feet.

The height of the base of triagular pyramid is h = 3.

The height of triangular pyramid is H = 5 feet.

The mass of the triangular pyramid = 56 kg.

The formula for the volume of the pyramid is,


\begin{gathered} V=(1)/(3)\cdot B\cdot H \\ =(1)/(3)\cdot((1)/(2)bh)\cdot H \\ =(1)/(6)b\cdot h\cdot H \end{gathered}

Substitute the values in the formula to determine the volume of pyramid.


\begin{gathered} V=(1)/(6)\cdot3\cdot4\cdot5 \\ =10 \end{gathered}

The formula for the density of the platic is,


\rho=(M)/(V)

Substitute the vlaues in the formula

User Ajay Singh
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