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Carbon-14 has a half-life of 5,730 years. If a sample contained 70. Ang originally, how much isleft after 17,190 years?

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Given data

*The carbon-14 has a half-life is t = 5730 years

*The amount of quantity contained is n = 70 mg

*The given time is T = 17190 years

The expression for the radioactivity decay equation is given as


N=n(0.5)^{(T)/(t)}

Substitute the values in the above expression as


\begin{gathered} N=70(0.5)^{(17190)/(5730)} \\ =8.75\text{ mg} \end{gathered}

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