Question

4. find the area of each sector between gondola cars Use 3.14 for pi and round to the nearest hundredth You must write out all the numbers you are multiplying together , meaning show your work for full credit ( 5 points )Central angle 8, radius 95ft5. The SkyWheel ride provides 3 complete revolutions and lasts approximately 10 minutes . If the diameter of the ferris wheel is 190 feet how far would you travel in those 3 revolutions ? Use 3.14 for and give your exact answer . You must write out all the numbers you are multiplying together , meaning , show your work for full credit ( 3 points ) +

Answer 1

Number 5:

The diameter of the Ferris wheel is given as

`d=190ft`

The formula to calculate the distance of one revolution is given below as

`\begin{gathered} C=2\pi r \\ \pi=3.14 \\ r=(190)/(2)ft=95ft \end{gathered}`

By substituting the values, we will have

`\begin{gathered} C=2\pi r \\ C=2*3.14*95ft \\ C=596.6ft \end{gathered}`

For three revolutions, we will have the distance to be

`\begin{gathered} D=596.6ft*3 \\ D=1789.8ft \end{gathered}`

Hence,

The distance he will travel in those 3 revolutions is

`\Rightarrow1789.8ft`

Number 4:

The formula for the area of a sector is given below as

`\begin{gathered} A=(\theta)/(360)*\pi r^2 \\ A=(8)/(360)*3.14*(95)^2 \\ A=629.74ft^2 \end{gathered}`

Hence,

The area of the sector to the nearest hundredth is

`\Rightarrow629.74ft^2`