The question requires us to calculate the mass (in grams) contained in 8.95 x 10^23 formula units of Na2O.
To solve this question, we first need to calculate the molar mass of the compound given (Na2O). To do that, let's consider the following atomic masses:
Na: 22.99 u
O: 15.99 u
Now, we calculate the molar mass of Na2O considering the atomic masses and the number of atoms of each element in the molecule:
Molar mass (Na2O) = (2 * 22.99) + (1 * 15.99) = 61.97 g/mol
Next, we can relate the amount of formula units given (8.95 x 10^23) with the Avogadro's number (6.02 x 10^23 mol^-1):
6.02 x 10^23 formula units ---------- 1 mol Na2O
8.95 x 10^23 formula units ---------- x
Solving for x, we have that there are 1.49 moles of Na2O in 8.95 x 10^23 formula units of this compound.
The last step is to convert the number of moles found (1.48 moles) into the mass of Na2O, using the molar mass previously calculated:
1 mol Na2O ---------- 61.97 g Na2O
1.48 mol Na2O ----- y
Solving for y, we have that there are 91.72 g of Na2O in 8.95 x 10^23 formula units of this compound.