Answer:
The integers are -5, -3 and -1.
Step-by-step explanation:
Let the first consecutive odd integer = x
• Then the next two consecutive odd integers = x+2 and x+4
The sum of the three integers is:
![x+(x+2)+(x+4)=3x+6](https://img.qammunity.org/2023/formulas/mathematics/college/75yqdok0lezgvkchvlgvvnqoc9rbcrqs70.png)
4 times the sum of three consecutive odd integers:
![\implies4(3x+6)](https://img.qammunity.org/2023/formulas/mathematics/college/6oqewbvsb1rx3yea1pitss8dh0yyn222qh.png)
The result is -36. Thus, we have the equation:
![4(3x+6)=-36](https://img.qammunity.org/2023/formulas/mathematics/college/f2efnubh21xy3zixlgtk1om7ld7xyjpp2k.png)
Solve for x:
![\begin{gathered} 3x+6=(-36)/(4) \\ 3x+6=-9 \\ 3x=-9-6 \\ 3x=-15 \\ x=-(15)/(3) \\ x=-5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/r7vvobshby38jr4xe7mt2xmue9papqh7yv.png)
Thus, the integers are:
![\begin{gathered} x=-5 \\ x+2=-5+2=-3 \\ x+4=-5+4=-1 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/qa3d2vikd28bhufh2dqu9z9vvdwv7d0fpe.png)
The integers are -5, -3 and -1.