Question

I need help graphing and solving the problem below.

Answer 1

The initial equation is:

`x+3y=9`

Now we write the equation in the slope intercept form so:

`\begin{gathered} 3y=-x+9 \\ y=-(1)/(3)x+3 \end{gathered}`

Now we know that the intercept with the y axis is 3, and we can calculate the intercept in the x axis by replacing y = 0 so:

`\begin{gathered} 0=-(1)/(3)x+3 \\ (1)/(3)x=3 \\ x=3\cdot3 \\ x=9 \end{gathered}`

Now we can graph the equation with the coordinates ( 0, 3 ) and ( 9, 0 ) so: