Given a deck of card, the sample space (T) is 52, there 13 spades (S), therefore the probability of drawing two spades on two cosecutive draws is given below
![\begin{gathered} n(T)=52 \\ n(S)=13 \\ Pr(S)=(13)/(52)=(1)/(4) \\ \text{ Since there is replacement} \\ Pr(S)\text{ and Pr(S) =}(1)/(4)*(1)/(4)=(1)/(16) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/pn6n01zcx5ikuxucoczsweroxcrltvxx12.png)
The probability of not picking two consecutive spades will be
![\begin{gathered} Pr(S_1S_2)^(\prime)=1-Pr(S_1S_2) \\ =1-(1)/(16)=(15)/(16) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/b8jpie5zw1hjs8yvel97ku8v5pnedueyrv.png)
The expected value for drawing two consecutive spades will be
![\begin{gathered} ExpectedValue=xP(x)_{} \\ x=23,P(x)=(1)/(16)_{} \\ ExpectedValue=23*(1)/(16)=(23)/(16)=1.44 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/jg23io6y3m1us9kge851sqknctzn329h3v.png)
The expected value for not drawing two consecutive spades will be