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The surface area of a right rectangular prism is 2f + 2t + 2r, where fis thearea of the front face, t is the area of the top face, and r is the area of theright side face. Show how to use the expression to find the surface areaof4 cmthe right rectangular prism at the right. Show your work.

The surface area of a right rectangular prism is 2f + 2t + 2r, where fis thearea of-example-1
User ABarrier
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1 Answer

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We are given the following formula for the surface area of a prism:


A=2f+2t+2r

"f" is the area of the front face, in this case, the front face is a rectangle, the area of a rectangle is given by the product of its base and its height. For the front face rectangle, its base is 8cm and its height is 4 cm, therefore, "f" is equal to:


f=(8\operatorname{cm})(4\operatorname{cm})=32\text{ cm}^2

Now, for "t", the area of the top face, is also a rectangle with a base of 8 cm and a height of 3 cm, therefore its area is:


t=(8\operatorname{cm})(3\operatorname{cm})=24\text{ cm}^2

For "r", we have a base of 3cm and a height of 4cm, therefore, the area is:


r=(3\operatorname{cm})(4\operatorname{cm})=12\text{ cm}^2

Replacing in the formula for the area of the prism, we get:


\begin{gathered} A=2f+2t+2r \\ A=2(32\text{ cm}^2)+2(24\text{ cm}^2)+2(12\text{ cm}^2) \end{gathered}

Solving the operations in the parenthesis, we get:


A=64+48+24

Solving the sum


A=136\text{ cm}^2

User Yura Bysaha
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