Question

Nth term of a sequence is 1/2 n^2+10 term closest to 100 clear explanation pleasse

Answer 1

Given:

`t_n=(1)/(2)n^2+10`
`\begin{gathered} 100=(1)/(2)n^2+10 \\ 90=(1)/(2)n^2 \\ 180=n^2 \\ n=\sqrt[]{180} \\ n=13.4164 \end{gathered}`

13 th term is closest to 100.