Question

Simplify the following
`{x}^(0) yz {}^( - 3)`

Answer 1

Given

`x^0yz^(-3)`

Solution

Recall

`a^0=1`
`\begin{gathered} x^0yz^(-3) \\ 1.yz^(-3) \end{gathered}`
`yz^(-3)`

Recall

`\begin{gathered} a^(-b)=(1)/(a^b) \\ so\text{ }z^(-3)=(1)/(z^3) \end{gathered}`

Therefore

`yz^(-3)=(y)/(z^3)`

The final answer

`x^0yz^(-3)=(y)/(z^3)`