359,844 views
30 votes
30 votes
What is the value of y in the solutions of the system of equations: 3x + 4y = 3 and 2x – 4y = 12?

User Tanvir
by
3.0k points

2 Answers

14 votes
14 votes
Step-by-step explanation:
Step 1) Solve the second equation for
y
2
x
+
y
=

8

2
x
+
2
x
+
y
=

2
x

8
0
+
y
=

2
x

8
y
=

2
x

8
Step 2) Substitute
(

2
x

8
)
for
y
in the first equation and solve for
x
:

3
x
+
4
y
=
12
becomes:

3
x
+
4
(

2
x

8
)
=
12

3
x
+
(
4
×

2
x
)
+
(
4
×

8
)
=
12

3
x
+
(

8
x
)
+
(

32
)
=
12

3
x

8
x

32
=
12
(

3

8
)
x

32
=
12

11
x

32
=
12

11
x

32
+
32
=
12
+
32

11
x

0
=
44

11
x
=
44

11
x

11
=
44

11

11
x

11
=

4
x
=

4
Step 3) Substitute

4
for
x
in the solution to the second equation at the end of Step 1 and calculate
y
:
y
=

2
x

8
becomes:
y
=
(

2
×

4
)

8
y
=
8

8
y
=
0
The Solution Is:
x
=

4
and
y
=
0
Or
(

4
,
0
)
User Lowcoupling
by
2.5k points
11 votes
11 votes

Answer:

y = -3

Step-by-step explanation:

3x + 4y = 3

2x - 4y = 12

5x = 15 Add the two equation together because the y terms are

opposite each other and goes out when you add the equations

x = 5

Substitute into the first equation and solve for y when x = 5

3x + 4y = 3

3(5) + 4y = 3

15 + 4y = 3

4y = 3 - 15

4y = -12

y = -3

User Vasudha
by
3.4k points
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