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Write the center radius and the equation of the circle in standard from shown on the graph

Write the center radius and the equation of the circle in standard from shown on the-example-1

1 Answer

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x^2+(y+2)^2=8^2

Step-by-step explanation:

We apply the equation of circle instandard form:


\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ \text{where the center of circle = (h, k)} \\ r\text{ = radius} \end{gathered}

We need to determine the center of circle from the graph given:

From the graph, the center is at 2 units below the origin (0, 0) on the y axis.

This coordinate corresponds to (0, -2)

The center (h, k) = (0, -2)

h = 0 and k = -2

The radius is the distance from the center of the circle to the circumference.

The distance is 8 units

radius = 8 units

Inserting the formula into the equation:


\begin{gathered} (x-0)^2+(y-(-2))^2=8^2 \\ x^2+(y+2)^2=8^2\text{ or} \\ x^2+(y+2)^2=\text{ 64} \end{gathered}

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