Question

Select the two values of x that are roots of this equation. x^2+3x-6=0

Answer 1

In order to find the roots of this quadratic equation, let's identify the coefficients a, b and c from the standard form and use them in the quadratic formula:

`\begin{gathered} ax^2+bx+c=0\\ \\ x^2+3x-6=0\\ \\ a=1,b=3,c=-6\\ \\ \\ \\ x=(-b\pm√(b^2-4ac))/(2a)\\ \\ x=(-3\pm√(9+24))/(2)\\ \\ x_1=(-3-√(33))/(2)\\ \\ x_2=(-3+√(33))/(2) \end{gathered}`

Therefore the answers are A and C.