Question

I need to round to tge narest tenth

Answer 1

`\lbrace8.4,0.6\rbrace`

Step by step explanation:

Solve for x:

`x^2-11x+5=-2x`

As a first step, solve using inverse operations to solve equations:

`\begin{gathered} x^2-11+2x+5=0 \\ x^2-9x+5=0 \end{gathered}`

Now, to solve this quadratic function we need to use the quadratic formula:

`\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{where,} \\ ax^2+bx+c=0\text{ is the form of the function} \end{gathered}`

Then, the solutions for the equation:

`\begin{gathered} x_1=\frac{9+\sqrt[]{(-9)^2-4(1)(5)}}{2(1)}=8.4 \\ x_2=\frac{9-\sqrt[]{(-9)^2-4(1)(5)}}{2(1)}=0.6 \end{gathered}`