Given:

The given complex number need to convert it a polar form
The angle (11π/6) lying on the fourth quadrant
So, cos (11π/6) will be (+) and sin (11π/6) will be (-)
The reference angle will be: 360 - (11π/6) = π/6
![\begin{gathered} \cos ((\pi)/(6))=\frac{\sqrt[]{3}}{2} \\ \\ \sin ((\pi)/(6))=(1)/(2) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/sf0fuavm2n9fs79kukojr3ny51y3lnwvx1.png)
So, the standard form of the given number will be:
![\begin{gathered} 2\cdot(\frac{\sqrt[]{3}}{2}-j(1)/(2)) \\ \\ =\sqrt[]{3}-j \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/rdn6nw64clah69kfzhvllo24p7wmdq0dp8.png)
So, the answer will be option B.