Given the function:
x^2 + 2x - 8
x^2 - 2x - 8
we are to find the zeros of the function.
To find the zero of a function, we find the root of the numerator.
That is, equsting the numerator to zero
x^2 + 2x - 8 = 0
lets get factor of the above eqaution
= x^2 - 2x + 4x + 8
x(x-2) + 4(x-2) = 0
so,
x + 4 = 0 OR x - 2 = 0
x + 4 = 0
x = -4
OR
x - 2 = 0
x = 2
so, x = -4, 2
Therefore the zeros of the function x^2 + 2x - 8 are -4, 2
x^2 - 2x - 8
So, the correct option is D which is -4, 2