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If a spring has a spring constant of 5 N/m and it is stretched 20 cm, what is the force of the Spring

1 Answer

6 votes

Answer:

1 N

Step-by-step explanation:

First the equation is momentum = Force / distance

20 cm = 0.2 m

5 N/m = F / 0.2 m

F = 1 N

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