If a spring has a spring constant of 5 N/m and it is stretched 20 cm, what is the force of the Spring

asked Apr 2, 2023 68.8k views

18 votes

7.0k points

Please log in or register to add a comment.

6 votes

Answer:

1 N

Step-by-step explanation:

First the equation is momentum = Force / distance

20 cm = 0.2 m

5 N/m = F / 0.2 m

F = 1 N

Armell answered Apr 6, 2023

6.9k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

7.8m questions

10.5m answers