Question

Given function f(x)=x^2-3xA) f(-2):B) f(3p):

Answer 1

`\begin{gathered} A)\text{ f(-2) = 10} \\ B)f(3p)=9p^2\text{ - p9} \end{gathered}`Step-by-step explanation:
`f(x)=x^2\text{ - 3x}`

A) To find f(-2), we will substitute -2 for x in f(x)

`\begin{gathered} f(-2)=(-2)^2\text{ - 3(-2)} \\ f(-2)\text{ = 4 + 6} \\ f(-2)\text{ = 10} \end{gathered}`

B) To find f(3p), we will substitute 3p for x in f(x)

`\begin{gathered} f(3p)=(3p)^2\text{ - 3(3p)} \\ f(3p)\text{ = (3p)(3p) - 9p} \\ f(3p)=9p^2\text{ - 9p} \end{gathered}`