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The pressure, P (in Ibs/in2), that a 160-poundperson's shoe exerts on the ground whenwalking varies inversely with the area, A (inin2 ), of the sole of the shoe. When theshoes have a sole area of 40 in2, the pressureis 4 lbs/in2. Find an equation that relatesthese variables.[?]P =

The pressure, P (in Ibs/in2), that a 160-poundperson's shoe exerts on the ground whenwalking-example-1

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For this problem we know that for a 160-poundperson with an area of 40 in^2 the pressure is 4 lbs/in^2

So then we can conclude that the pressure is calculated with this operation:


P=(160lb)/(40in^2)=4(lb)/(in^2)

Then we can create a generic formula forthe pressure and would be given by:


P=(F)/(A)

Where F = force and A= area

User Anders Lindahl
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