Question

Enter the range of values for x:B15С2x - 1048°18[ ?[?]

Answer 1

`\begin{gathered} \text{INTERIOR ANGLES OF A QUADRILATERAL ADDS UP 360 } \\ \text{DEGREEES, THEN} \\ 2x-10+B+A1=180 \\ 48+D+A2=180 \\ 2x-10+48+B+D+A1+A2=360 \\ \text{then we have} \end{gathered}`
`\begin{gathered} \text{If the angles are equal, one has }2x-10=48 \\ 2x=48+10 \\ 2x=58 \\ x=(58)/(2) \\ x=29 \\ but,\text{ interior angles of a triangle add up 180 } \\ \text{then} \end{gathered}`