What is the value of p in the equation y^2= –12x

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asked Nov 19, 2023 202k views

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Astrom · Answer 1 · 2023-11-23T00:33:23+0000

Answer:

p = -3

Step-by-step explanation:

The equation of the parabola is:

We will calculate for ''p'' as shown below:

$\begin{gathered} y^2=-12x \\ \text{Rewriting the equation in vertex form, we have:} \\ x=-(y^2)/(12) \\ We\text{ will use vertex form to determine the values of: }a,h,k \\ x=a(y-k)^2+h \\ \Rightarrow a=-(1)/(12) \\ \Rightarrow k=0 \\ \Rightarrow h=0 \\ Since\text{ }the\text{ value of ''a'' is negative, the parabola opens left} \\ (h,k)=(0,0) \\ We\text{ will find }^(\doubleprime)p^(\doubleprime)\text{ using the formula given below:} \\ p=(1)/(4a) \\ p=(1)/(4(-(1)/(12))) \\ p=(1)/(-(1)/(3)) \\ p=-3 \\ \\ \therefore p=-3 \end{gathered}$

Therefore, p equals -3

What is the value of p in the equation y^2= –12x

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