Question

4^4÷ (3^ 2 + (3^2 – 5^0))

Answer 1

Given:

`4^4/(3^2+(3^2-5^0))`

To: Solve the given expression

Apply the laws basic of operation PODMAS

The operation consist of:

Parentheses

Division

Let us solve the parentheses first, then division

`\begin{gathered} 4^4/(3^2+(3^2-5^0)) \\ (3^2+(3^2-5^0))=(3^2+(9-1)) \\ (3^2+(9-1))=(9+8)=17 \\ \text{Therefore, we have:} \\ 4^4/(3^2+(3^2-5^0))=256/17=15(1)/(17) \end{gathered}`

Hence, the final answer is 15 1/17